This section is from the book "The English And American Mechanic", by B. Frank Van Cleve. Also available from Amazon: The English And American Mechanic.
Divide the weight of the modulus of elasticity of the material by weight of 1 foot of it and the quotient will give the height in feet.
From a series of elaborate experiments by Mr. E. Hodgkinson for the Railway Commission, he deduced the following formulae for the extension and compression of cast and wrought iron: e e2
Cast-iron Extension : 13,934,040-----2,907,432,000 - = W.
l l2 c c2
Cast-iRon Compression: 12,931,560-----522,979,200 - = W, e and c rel l2 presenting the extension and compression, and l the length in inches.
What weight will extend a bar of cast-iron, 4 inches square and 10 feet in length, to the extent of .2 inch?
2 .22 13,934,040X-------2,907,432,000-----= 23223.4 - 8076.2 = 15147.2, which X 4 ins.
120 1202
= 60588.8 lbs.
 
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