This section is from the book "Scientific American Reference Book. A Manual for the Office, Household and Shop", by Albert A. Hopkins, A. Russell Bond. Also available from Amazon: Scientific American Reference Book.
9X12 cm | ||
12X16 | ||
12X18 | ||
13X18 | ||
12X20 | ||
18X24 | ||
21X29 | ||
24X30 | ||
27X33 | ||
30 X 38 | ||
40X50 | ||
50 X 60 | ||
3.6X 4.7 | inches |
4.7X 6.3 | |
4.7X 7.0 | |
5.1X 7.0 | |
4.7X 7.8 | |
7.0X 9.4 | |
8.2X10.6 | |
9.4X11.8 | |
10.6X12.9 | |
11.8X14.1 | |
15.7X19.6 | |
19.6X23.6 |
The following data are useful in calculations relating to air:
1. To find the quantity of nitrogen by volume corresponding to 1 volume of oxygen, multiply by 3.770992.
2. To find the quantity of oxygen by volume corresponding to 1 volume of nitrogen, multiply by 0.265182.
3. To find the quantity of nitrogen by weight corresponding to 1 part by weight of oxygen, multiply by 3.313022.
4. To find the quantity of oxygen by weight corresponding to 1 part by weight of nitrogen, multiply by 0.301839.
5. To find the quantity of nitrogen by volume corresponding to 1 part by weight of oxygen, multiply by 2.6365411.
6. To find the quantity of oxygen by volume corresponding to 1 part by weight of nitrogen, multiply by 0.2730071.
7. To find the quantity of nitrogen by weight corresponding to 1 part by volume of oxygen, multiply by 3.6629154.
8. To find the quantity of oxygen by weight corresponding to 1 part by volume of nitrogen, multiply by 0.3792848.
Saturate unglazed paper with a solution of 1 oz. of pure lead acetate in half a pint of rain water; let it partially dry, then expose in the room suspected of containing sewer gas. The presence of the latter in any considerable quantity soon darkens or blackens the test paper.
 
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